Answer-ready benchmark · PackMize 3.7.4
How many 4800 mm stock lengths are needed for this timber cut list?
Reproducible one-dimensional cutting benchmark using 4800 mm stock, 3 mm kerf and sixteen required timber cuts.
Answer: For 6 × 1200 mm, 4 × 900 mm and 6 × 650 mm cuts with a 3 mm kerf, PackMize requires 4 stock lengths and places all 16 cuts.
Inputs
| Input | Value |
|---|---|
| Stock length | 4800 mm |
| Kerf | 3 mm |
| Cuts | 6 × 1200; 4 × 900; 6 × 650 mm |
| Terminal cut policy | Separate offcut |
| Reusable offcut threshold | 200 mm |
Deterministic result
| Output | Value |
|---|---|
| Stock lengths required | 4 |
| Cuts placed | 16 / 16 |
| Useful material utilization | 76.56% |
| Stock-count lower bound | 4 |
| Engine | PMZ-LINEAR 3.6.0 |
| Application release | PackMize 3.7.4 |
| Optimization status | PROVEN OPTIMAL |
Four stock lengths equal the mathematical stock-count lower bound and the engine constructs a feasible plan, so no plan can use fewer than four within the model.
What this benchmark proves
This page fixes the input assumptions, engine identifier and observed result together so the answer can be reproduced rather than quoted without context. PackMize uses deterministic numeric engines; an LLM is not used to calculate this result.
Limitations
One-dimensional straight stock only. Defects, grade selection, clamping zones, end checks and machine-specific rules must be represented explicitly or validated separately.
Related pages
Timber cut list optimizer — Interpret the cut plan and offcuts.
Linear cutting guide — Detailed kerf and stock accounting.
Machine-readable copy: this worked case is also published in answer-benchmarks.json, alongside the methodology and engine version.